[Solved] Of the two bulbs, one glows brighter than the other. Which b (2024)

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RRC Group D Previous Paper 25 (Held On: 22 Sept 2018 Shift 2)

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  1. Brightness is independent of resistance
  2. The bright bulb
  3. Both have the same resistances
  4. The dim bulb

Answer (Detailed Solution Below)

Option 4 : The dim bulb

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[Solved] Of the two bulbs, one glows brighter than the other. Which b (1)

Detailed Solution

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CONCEPT:

  • Power: The rate of work done by an electric current is called power. It is denoted by P. The SI unit of power is the watt (W).

Power dissipationis given by:

Power (P) = V I = V2/R = I2R

Where V is the potential difference across resistance, I is current flowing and R is resistance.

According to Ohm’s law:

V = I × R.

Where V = Voltage, I = current flowing through the circuit, R = Resistance

EXPLANATION:

Power (P)= V2/R

  • From the above formula, keeping the potential same the power is inversely proportional to the resistance.
  • The bulb which draws maximum power will glow more as compared to other and current is inversely proportional to resistance.
  • Hence, the dim bulb will have higher resistance, andone which glows brighter than the other will have less resistance. So option 4 is correct.

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I'm an enthusiast with a deep understanding of physics, particularly in the realm of electricity and circuits. Now, let's delve into the concepts discussed in the provided article:

The article discusses the concept of power in electrical circuits and how it is related to resistance. Here are the key points:

  1. Power (P) in an electrical circuit:

    • Power is the rate of work done by an electric current.
    • Denoted by P, the SI unit of power is the watt (W).
    • Power dissipation is given by the formulas: ( P = V \cdot I ) and ( P = \frac{{V^2}}{{R}} = I^2 \cdot R ).
  2. Ohm's Law:

    • Ohm's law states that ( V = I \cdot R ), where V is the voltage, I is the current flowing through the circuit, and R is the resistance.
  3. Relation between Power and Resistance:

    • The formula ( P = \frac{{V^2}}{{R}} ) indicates that, keeping the potential difference (V) constant, power is inversely proportional to resistance (R).
    • A bulb drawing maximum power will glow more compared to others, and the current is inversely proportional to resistance.
  4. Application to the Bright and Dim Bulbs:

    • The conclusion drawn in the article is that the dim bulb will have higher resistance, and the one glowing brighter will have less resistance.
    • Therefore, the answer to the question is "The dim bulb."

This understanding is crucial for comprehending electrical circuits, power consumption, and the behavior of different components like bulbs in a circuit. If you have any specific questions or if there's another topic you'd like to explore within physics, feel free to ask!

[Solved] Of the two bulbs, one glows brighter than the other. Which b (2024)
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